The probability that less than 59 customers arrive in an hour during tomorrow's morning rush will be 0.0521.
From the information given, it was stated that coffee shop serves an average of 72 customers per hour during the morning rush and we eat to find the probability that less than 59 customers arrive in an hour during tomorrow's morning rush.
This will be done by using the Poisson distribution:
P(x <= 58) = [e^-72 × (72)^x]/x!
= 0.0521
Therefore, the probability that less than 59 customers arrive in an hour during tomorrow's morning rush will be 0.0521.
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