Respuesta :

Answer:

5

Step-by-step explanation:

C(4, 7)

D(7, 11)

x₁ = 4; y₁ = 7

x₂ = 7; y₂ = 11

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(7 - 4)² + (11 - 7)²]

d = √(3² + 4²)

d = √(9 + 16)

d = √25

d = 5

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's use distance formula :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{(x2 - x1) {}^{2} + (y2 - y1)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{(7 - 4) {}^{2} + (11 - 7) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {3}^{2} + 4 {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{9 + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{25} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 5[/tex]

So, the distance between them is 5 units ~