Find the distance CD rounded to the nearest tenth
C=(4,7) D=(7,11)

Answer:
5
Step-by-step explanation:
C(4, 7)
D(7, 11)
x₁ = 4; y₁ = 7
x₂ = 7; y₂ = 11
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
d = √[(7 - 4)² + (11 - 7)²]
d = √(3² + 4²)
d = √(9 + 16)
d = √25
d = 5
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's use distance formula :
[tex]\qquad \sf \dashrightarrow \: \sqrt{(x2 - x1) {}^{2} + (y2 - y1)} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{(7 - 4) {}^{2} + (11 - 7) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ {3}^{2} + 4 {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{9 + 16} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{25} [/tex]
[tex]\qquad \sf \dashrightarrow \: 5[/tex]
So, the distance between them is 5 units ~