If the pendulum bob took 0.20s to swing from a to b to c then the length of the pendulum would be 0.01 m. Here's how,
To calculate the period of a simple pendulum, we use the formula,
T = 2π√(L/g), but the time period is already given in the question which is 0.20 s, Therefore, we have to calculate the length of the pendulum, for which the formula is,
⇒ L = (T/ 2π)² * g,
⇒ L = [tex]\frac{T^{2}g}{4pi^{2}}[/tex],
Where, L is the length of the pendulum,
T is the time period of the pendulum, and
g is the acceleration due to gravity.
Hence, from above the question we have given, T = 0.20 s, we have to calculate the length of the pendulum.
⇒ L = [tex]0.20^{2}[/tex] × 9.8/ 4 × ([tex]3.14^{2}[/tex])
⇒ L = 0.01 m.
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