The function f(t)=-16 + 100 models the height of a ball, in feet, dropped from a 100-foot rooftop at time t, in seconds.
What is the average rate of change for the function over the interval 0 OA 36 ft; the height of the ball above the ground at 1 second
OB. -32 ft/s; the average change in altitude of the ball each second over that interval
OC. 32 ft/s; the average change in altitude of the ball each 2 seconds
OD. -64 ft; the distance the ball fell in 2 seconds

Respuesta :

Using it's concept, it is found that the average rate of change of the function during the interval from 0 to 2 seconds is given by:

B. -32 ft/s; the average change in altitude of the ball each second over that interval.

What is the average rate of change of a function?

The average rate of change of a function is given by the change in the output divided by the change in the input. Hence, over an interval [a,b], the rate is given as follows:

[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]

In this problem, the function is given by:

f(t) = -16t² + 100.

The outputs are given as follows:

  • f(0) = -16(0)² + 100 = 100.
  • f(0) = -16(2)² + 100 = 36.

Hence the average rate of change is given by:

r = (36 - 100)/(2 - 0) = -32 ft/s.

And the correct option is:

B. -32 ft/s; the average change in altitude of the ball each second over that interval.

More can be learned about the average rate of change of a function at https://brainly.com/question/24313700

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