pythagorean theorem
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[tex]3^2 + b^2 = 11^2 \\ \\ 9+b^2 = 121 \\ \\ b=\boxed{\sqrt{112}}[/tex]
Answer:
b = √112
Step-by-step explanation:
a^2 + b^2 = c^2
3^2 + b^2 = 11^2
b^2 = c^2 − a^2
b^2 = 11^2 − 3^2
√b^2 = √11^2 − 3^2
b =√11^2 − 3^2
b = √11^2 − 3^2
b = √121 − 9
b = √112