Respuesta :
The speed and pressure at another end will be 9 m/sec and -31500 pascals.
What is gauge pressure?
The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.
Given data in problem is;
For horizontal pipe, Z₁=Z₂
Pressure at end 1, P₁ = 4500Pa
Speed at end 1, V₁ = 3 m/sec
Speed at end 2, V₂ = ? m/sec
Area of cross-section at end 1,A₁ =A
Area of cross-section at end 1,A₂ = A/3
From the continuity equation;
A₁V₁=A₂V₂
A× 3 = (A/3)×V₂
V₂ = 9 m/sec
From Bernoulli's equation;
[tex]\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa[/tex]
Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.
To learn more about the gauge pressure, refer to the link;
https://brainly.com/question/14012416
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