pezmachine9000
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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m. (It is not a very smart idea to play soccer on the roof of tall buildings.)
The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.
How much energy was lost to air friction? The ball is kicked without a spin.

A soccer ball is kicked from the top of one building with a height of H1 302 m to another building with a height of H2 120 m It is not a very smart idea to play class=

Respuesta :

onyebuchinnaji

The energy lost to the air due to friction is 37.7 J.

Energy lost to the air due to friction

The energy lost to the air due to friction is determined from the change in kinetic energy of the ball.

ΔK.E = K.Ef - K.Ei

ΔK.E = ¹/₂mv² - ¹/₂mu²

ΔK.E =  ¹/₂m(v² - u²)

ΔK.E = ¹/₂(0.45)(19.89² - 15.1²)

ΔK.E = 37.7 J

Thus, the energy lost to the air due to friction is 37.7 J.

Learn more about kinetic energy here: https://brainly.com/question/25959744

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