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The speed of a bus is reduced uniformly from 20 m/s to 10 m/s while traveling 60 m. (a)
Compute the acceleration. (b) How much farther will the bus travel before coming to rest,
provided the acceleration remains constant? (c) Draw a diagram showing the motion from start to
finish of the bus.

Respuesta :

pstnonsonjoku

The bus will travel a further 20 m before coming to rest.

What is acceleration?

The term acceleration has to do with a change in velocity with time. Now we have;

u = 20 m/s

v = 10 m/s

s =  60 m

Now;

v^2 = u^2 -2as

v^2 -  u^2 = -2as

(10)^2 - (20)^2 = - 2 * a * 60

a = (10)^2 - (20)^2/ - 2 * 60

a = 100 - 400/ - 2 * 60

a = 2.5 m/s^2

At that time;

v = 0 m/s

u = 20 m/s

a = 2.5 m/s^2

s = ?

Hence;

u^2 = 2as

s = u^2/2a

s = (20)^2/ 2 *  2.5

s = 400/5

s = 80 m

Hence, the bus will travel a further 20 m before coming to rest.

Learn more about acceleration:https://brainly.com/question/12550364

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