567 teams participate in a football tournament. If each team plays against every other team only once, how many matches will be played in total?

Respuesta :

Given that, 567 teams participate in a football tournament, If each team plays against every other team only once, number of matches played in total is 160461.

How many matches will be played in total?

To determine the total number of matches played, we apply Combination.

ⁿCr = n! / r!( n-r )!

Given that;

  • Number of team n = 567
  • Number of team in r match a = 2

We substitute

[tex]^nC_r = \frac{n!}{r!(n-r)!} \\\\^nC_r = \frac{567!}{2!(567-2)!} \\\\^nC_r = \frac{567!}{2!(565)!}\\\\^nC_r = \frac{567 * 566 * 565!}{2!(565)!} \\\\Cancel-common - factor: 565!\\\\^nC_r = \frac{567 * 566 }{2!} \\\\^nC_r = \frac{567 * 566 }{2*1}\\\\^nC_r = \frac{ 320922 }{2} \\\\^nC_r = 160461[/tex]

Given that, 567 teams participate in a football tournament, If each team plays against every other team only once, number of matches played in total is 160461.

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