The easiest way to solve a modulu problem is by
2^100/3
=3√2^100
=3√2^99×2
=2^33×3√2
The [tex]\sqrt{2}[/tex] is the reminder.
The easiest way to find the remainder that only work with specific numbers is that this can be done when one solve the division by the use of a calculator by:
First if you answer is in decimal form, you have to subtract the whole number and later multiply the decimal value that is said to be left by the divisor of the original problem. The outcome is your remainder.
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