Someone help please!?!

Answer: a≈6,1.
Step-by-step explanation:
The sine theorem states:
[tex]\boxed {\frac{a}{sinA^0} =\frac{b}{sinB^0}= \frac{c}{sinC^0} }[/tex], ⇒
[tex]a=\frac{c*sinA^0}{sinC^0}[/tex]
m∡A=180°-(m∡B°+m∡C°)
=180°-(68°+76°)
=180°-144°
=36°. ⇒
[tex]a=\frac{c*sin36^0}{sin76^0}\\ =\frac{10*sin36^0}{sin76^0} \\\approx6,1.[/tex]
Good luck an' have a nice day!