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A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.

A thin flexible gold chain of uniform linear density has a mass of 171 g It hangs between two 300 cm long vertical sticks vertical axes which are a distance of class=

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okpalawalter8

The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

[tex]Q=45 \textdegree[/tex]

What is the magnitude of the force on the left-hand pole.?

Generally, the equation for Force is  mathematically given as

[tex]F=\frac{mg}{sin\theta}[/tex]

Therefore

[tex]F=\frac{17.1*10^{-3}*9.8}{sin45}[/tex]

F=0.237N

Considering horizontal

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

[tex]tan\theta=lv/ln\\\\tan\theta=30/30\\\\\theta=tan^{-1}\\\\[/tex]

[tex]Q=45 \textdegree[/tex]

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