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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0 m. (It is not a very smart idea to play soccer on the roof of tall buildings.)

The ball is kicked with a speed of v0 = 15.10 m/s at an angle of θ = 74.1° with respect to the horizontal. The mass of a size 5 soccer ball is m = 450 g. When the ball lands on the other building, its speed is 19.89 m/s.

How much energy was lost to air friction? The ball is kicked without a spin.

37.71 J is incorrect.

A soccer ball is kicked from the top of one building with a height of H1 302 m to another building with a height of H2 120 m It is not a very smart idea to play class=

Respuesta :

onyebuchinnaji

The  energy was lost to air friction is determined as 42.56 J.

Energy lost due to friction

The energy lost due to friction is calculated as follows;

ΔE = ΔK.E + ΔP.E

where;

  • ΔK.E is change in kinetic energy
  • ΔP.E is change in potential energy

ΔE = ¹/₂(0.45)(19.89² - 15.1²) + (0.45)(9.8)(12 - 30.2)

ΔE = 37.7 - 80.26

ΔE = -42.56 J

Thus, the  energy was lost to air friction is determined as 42.56 J.

Learn more about kinetic energy here: https://brainly.com/question/25959744

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