contestada

The length of the rectangular poster is 5 more inches than it’s width. The area of the poster is 72 square inches. Solve for the dimensions (length and width) of the poster.

Respuesta :

sarajeffries7

Answer:

so, the width of the poster is 8.185 inches  [rounded]  /   √67 inches

and the length of the poster is 13.185 inches [rounded]  / √67 + 5 inches

Step-by-step explanation:

( area can be found with the formula l × w [length × width]  )

I will call the width "x"

w  ·  l  = 72

x  ·  x + 5 = 72

          - 5    - 5

x · x = 67

x² =  67

√x²  =  √67

x ≈ 8.185

(x = √67)

so, by adding 5 inches, we get that

x + 5

8.185 + 5     [√67 + 5]

length = 13.185

so, the width of the poster is 8.185 inches  [rounded]  /   √67 inches

and the length of the poster is 13.185 inches [rounded]  / √67 + 5 inches