Find the length of diagonal BC of ABCD to the nearest hundredth.

The length of BC as shown in the diagram is 6.32units
The formula for calculating the distance between two points is expressed as:
D = √(x2-x1)²+(y2-y1)²
Given the following coordinate points (3, 6) and (5, 0)
Substitute
BC = √(0-6)²+(5-3)²
BC = √(36+4)
BC = √40
BC = 6.32 units
Hence the length of BC as shown in the diagram is 6.32units
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