The measure of ∠P to the nearest 10th of a degree is 84.8°
From the question, we are to determine the measure of ∠P
From the law of cosines, we can write that
[tex]cos \ P=\frac{o^{2}+q^{2}-p^{2} }{2oq}[/tex]
From the given information,
o = 500 cm
p = 600 cm
q = 380 cm
Putting the parameters into the formula, we get
[tex]cos \ P=\frac{500^{2}+380^{2}-600^{2} }{2\times 500 \times 380}[/tex]
[tex]cos \ P =\frac{34400}{380000}[/tex]
[tex]cos \ P =0.0905[/tex]
P = cos⁻¹(0.0905)
P = 84.8076
P ≅ 84.8°
Hence, the measure of ∠P to the nearest 10th of a degree is 84.8°
Learn more on the Law of Cosines here: https://brainly.com/question/20890746
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