Can someone please answer this, ill give you brainliest Would be very appreciated.

Answer:
Given function:
f(t) = (-16t - 2)(t - 1)
The zeros of the function are the values of t when f(t) = 0
⇒ f(t) = 0
⇒ (-16t - 2)(t - 1) = 0
⇒ (t - 1) = 0 ⇒ t = 1
⇒ (-16t - 2) = 0 ⇒ t = -2/16 = -1/8
The zeroes tell us the time (in seconds) when the ball is at ground level (when its height is zero).
Since time is not negative, only one zero is meaningful: t = 1
Therefore, the total journey of the ball, from throwing it to it hitting the ground, is 1 second.
The height the ball is thrown can be determined by inputting t = 0 into the function:
⇒ f(0) = (-16(0) - 2)(0 - 1)
⇒ f(0) = (0 - 2)(0 - 1)
⇒ f(0) = (-2)(-1)
⇒ f(0) = 2
Therefore, the height from which the beach ball is thrown is 2 ft.
Equation: y = (-16t-2)(t -1)
1) Finding zeros of the function?
To find zero's of the function y = 0
(-16t-2)(t -1) = 0
-16t - 2 = 0, t - 1 = 0
t = 2/-16, t = 1
t = -0.125, 1
2) What do the zero's tell us? Are they meaningful?
Answer: It tells us that the time is 1 seconds when the height of the ball is 0 or at rest.
3) From what height is the ball thrown?
Insert t = 0
y = (-16(0)-2)((0) -1)
y = 2
Ball thrown from 2 feet.