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Select the correct answer.
What is the approximate solution to this equation?
15(3)2+ = 90
=
2log
a = log3
O
210g3
t = log 6
O
log 6
210g3
=
log3
2log 6

Select the correct answer What is the approximate solution to this equation 1532 90 2log a log3 O 210g3 t log 6 O log 6 210g3 log3 2log 6 class=

Respuesta :

Answer:

C) [tex]x=\frac{\log(6)}{2\log(3)}[/tex]

Step-by-step explanation:

[tex]15(3)^{2x}=90\\\\3^{2x}=6\\\\2x=\log_3(6)\\\\2x=\frac{\log(6)}{\log(3)}\\\\x=\frac{\log(6)}{2\log(3)}[/tex]

Remember to use the change of base formula, which states that [tex]\log_a(b)=\frac{\log(b)}{\log(a)}[/tex] so that everything has the same base of 10

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