Answer:
x = 2, x = 3
Step-by-step explanation:
[tex]\mathrm{Given:}\begin{bmatrix}5x-4y=-2\\ 2x+4y=16\end{bmatrix}[/tex]
[tex]\mathrm{Step\;by\;step\;solving}:[/tex]
[tex]\mathrm{Isolate\;x\;for\;5x-4y=-2:\;x=\frac{-2+4y}{5}}[/tex]
[tex]\mathrm{Then\;substitute\:}x=\frac{-2+4y}{5}[/tex]
[tex]\begin{bmatrix}2\cdot \frac{-2+4y}{5}+4y=16\end{bmatrix}[/tex]
[tex]\mathrm{Simplifying}: \begin{bmatrix}\frac{-4+28y}{5}=16\end{bmatrix}[/tex]
[tex]\mathrm{Next\;Isolate\;y\;for\;\frac{-4+28y}{5}=16}:y=3[/tex]
[tex]\mathrm{Since,\:}x=\frac{-2+4y}{5}[/tex][tex]\mathrm{and\;y\;=\;3}[/tex]
[tex]\mathrm{Then, substitute\:}y=3[/tex]
[tex]\mathrm{So,x=\frac{-2+4\cdot \:3}{5}}[/tex]
[tex]\mathrm{Solving:\;x=2}[/tex]
[tex]\mathrm{Hence,the\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]
[tex]x=2,x=3[/tex]
~Kavinsky~
