A projectile is shot with the initial speed, it follows the motion called projectile motion. The height of the cliff is 44.91 m.
What is initial speed?
The speed at the start of the motion is the initial speed.
The horizontal distance is
x = v₀ sin θ. t
Substitute 26.5 for θ, 24 for x and 8.94 m/s for x, we get the time taken to complete the journey.
t = 24/ (8.94 cos26.5) = 3 s
Maximum height reached
H = v₀²sin²θ/2g
H = (8.94)² x sin²( 26.5) /(2 x 9.8)
H =0.8118 m
The height of the cliff is obtained by the equation of motion
0.8118 - h = -1/2 gt² +v₀sinθ.t
Substitute the values, we get
h =0.8118 +1/2x9.8x (3)²
h =44.911m
Thus, the height of the cliff is 44.91 m.
Learn more about initial speed.
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