What are the domain, range, and asymptote of h(x) = (1.4)x + 5?

domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5
domain: {x | x > 5}; range: {y | y is a real number}; asymptote: y = 5
domain: {x | x > –5}; range: {y | y is a real number}; asymptote: y = –5
domain: {x | x is a real number}; range: {y | y > –5}; asymptote: y = –5

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Answer:

The answer is

A.) Domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5

Step-by-step explanation:

For every real x, (1.4)x is always positive, therefore the range would be y > 0, but (1.4)x + 5 adds 5 to every integer in the original range. This suggests that the real range is y | y > 5, or all positive values bigger than 5.

This is the sole choice for the range that A has, therefore, it should. (The other two characteristics hold true, as can be any real integer and lim h(x) = 5 x, implying that y = 5 is a horizontal asymptote of h(x).)

Therefore, A.) Domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5 is your answer.

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Submitted on 4/20/2022 at 1:37 PM

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Answer:

OPTION A

Step-by-step explanation:

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