Find the third side, round the nearest 10th

Answer:
11.9
Step-by-step explanation:
Pythagorean theorem:
[tex]a^2+b^2 = c^2[/tex]. where a and b are the sides and c is the hypotehnus (the side in front of the 90 degree angle)
[tex]22^2 + b^2 = 25^2\\484 + b^2 = 625\\b^2 = 625-484\\b^2 = 141\\b = \sqrt{141} \\b = 11.9[/tex]
Answer:
11.9
Step-by-step explanation:
This is a right triangle so I can solve this with the pythagorean theorem.
Set up the equation 22²+x²=25² x would be the third side
Simplify, 484+x²=625
Subtract from both sides 484-484+x²=625-484
x²=141
Find the square root of 141 to get x
The square root of 141 is approximately 11.9 rounded to the nearest tenth.