find the vertical asymptote(s).

Answer:
x = 1
Step-by-step explanation:
To find the vertical asymptote(s) we set the denominator to 0, but first we have to factor and simplify the function
[tex]f(x)=\frac{(x+1)(x-7)(x+10)}{(x-1)(x-7)(x+10)}[/tex]
step 1 the function is already factored so we just have to simplify it by canceling like terms
[tex]f(x)=\frac{x+1}{x-1}[/tex]
step 2 set denominator to 0 and solve for x
x - 1 = 0
step 3 add 1 to both sides
x = 1
Answer: x = 1
By "doing the math" from the function given:
Given:
[tex]f (x) =\displaystyle \frac{(x+1)(x-7)(x-10)}{(x-1)(x-7)(x-10)}[/tex]
Terms in both the numerator and denominator are equal to 1:
[tex]f (x) =\displaystyle \frac{(x+1)}{(x-1)}[/tex]
We cannot have a denominator equal to 0, because you cannot divide by 0, so the vertical asymptote is x = 1 since 1 - 1 = 0. This can also be found by setting the denominator equal to 0 and solving for x.
By graphing:
A vertical asymptote, put simply, is a vertical line "within" the domain, but not a part of the graph. I will graph the equation given and see what we come up with.
-> See attached
Either way, the answer to your problem is:
x = 1