Respuesta :
Answer:
8/9
Step-by-step explanation:
A fraction that has denominator factors of 2 or 5 (only) will be finite in length. It will not be a repeating decimal fraction. This eliminates choices B and D.
The number of 9s in the denominator of a repeating decimal fraction will be equal to the number of repeating digits. The fraction 0.8888... has one repeating digit (8), so it can be written as 8/9.
_____
Additional comment
The fraction 80/99 will be the 2-digit repeating decimal 0.808080...
The fraction 1111/1250 evaluates to 0.8888, a 4-digit decimal fraction that does not repeat.
__
A fraction such as 0.142857...(6-digit repeat) can be written as ...
124857/999999 . . . . denominator has 6 nines
This fraction reduces to 1/7.
[tex] \begin{gathered}\begin{gathered}\boxed{\begin{array}{}\sf { \rightarrow \: \red{i \: dont \: know \: anymore}}\end{array}}\end{gathered} \end{gathered}[/tex][tex] \begin{gathered}\begin{gathered}\boxed{\begin{array}{}\sf { \rightarrow \: \red{i \: dont \: know \: anymore\:\color{green}☘}}\end{array}}\end{gathered} \end{gathered}[/tex]
[tex] \color {blue} \rule {1pt} {100000pt} [/tex]