Population will be 6 times of present population in 291 years.
What is the population of a city ?
The number of people in the city at a particular time is called population of the city.
How to find the required population ?
Present population of the city = 52000
According to the problem, Population doubles in size in every 97 years.
After 97 years, the population = Double of present population
= 2 × 52000 = 104000
Population in 97 years = 104000
Population in 1 year = [tex]\frac{104000}{97}[/tex]
So, population in 291 years = [tex]\frac{104000}{97}[/tex]× 291 = 104000×3 = 312000
Population in 291 years from now = [tex]\frac{312000}{52000}[/tex] = 6 times
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