KatieT2024
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How many grams of air are required to complete the combustion of 186 g of phosphorus (M= 31 g/mol) to diphosphorus pentoxide, assuming the air to be 23% oxygen by mass?
4P(s) + 5O2(g) — 2P2Os(s)

Respuesta :

Answer:

1043.5 g of air  to the nearest tenth.

Explanation:

4P + 5O2 ---> 2P2O5

4*31 g P reacts with 5*32 g oxygen

124 g   ..   ..   .   ....  .   160g oxygen

186 g   ..   ..   ..   ..   ..   (160*186)/124 g oxygen

-  so the mass of air required =  [(160*186)/124] / 0.23

= 240 / 0.23

= 1043.5 g of air.

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