Question 2 (1 point)
A group of friends is cooking an exotic stew in a house in South Florida. One of the
steps of the recipe is that they have to cool off the cooking mixture from 81.70 °C to
49.10 °C. The pot is too big to put it in a fridge for cooling down faster, the cooking
mixture weighted 34.6 kg. Fortunately, one of the friends remembered
thermochemistry and suggested that they put the pot in the small pool that is at the
house to cool it off faster. The pool was not heated and its temperature before
putting the pot with the stew was 19.24 °C. Given that the mass of water in the pool
was 4,825.6 kg, and the specific heat capacity of the pool is 4.30 J/(g°C) and that of
the cooking mixture is 4.20 J/(g°C), what is the final temperature of the pool after
the cooking mixture cooled down to the temperature needed by the recipe?
Your Answer:
Answer
units

Respuesta :

Knowing that the system will attin a state of thermal equilibrium, the final temperature of the system is 19.24°C.

What is Thermochemistry?

The term thermochemistry has to do with the heat evolved or absorbed in a chemical reaction.

Now we know that the heat gained by the pool is equal to the heat lost by the stew. Hence;

34.6  *  4.20 * ( 81.70 - T) =  4,825.6 *  4.30 * (T - 19.24)

11873 - 145.3T = 2075008T - 39923153.92

11873 + 39923153.9 = 2075008T + 145.3T

39935026.92 = 2075153.3T

T = 39935026.92/2075153.3

T = 19.24°C

Learn more about thermal equilibrium: https://brainly.com/question/27132799