consider the system of linear inequalities {y<1/2x-1, y>2x+3} Which points are in the solution set?
a. (-4,-3)
b. (1,3)
c. (-5,-7)
d. (3,0)
e. (-6,-5)
f. (-7,-2)
g. (-4,-4)
h. (-3,-3)

The points that are a solution to the set are points in the area of overlap created by the two equations graphed. Points that are on a line in the overlap, but not over, are not a solution because the equations do not include "equal to."

See attached for the graph.

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MrRoyal MrRoyal · Answer 2 · 2022-04-25T09:35:54+02:00

The solution set of y < 1/2x - 1 and y > 2x + 3 are their true values

The solution set of the system of linear inequalities are (-6,-5) and (-4,-4)

How to determine the solution set?

The system of linear inequality is given as:

y < 1/2x - 1

y > 2x + 3

Start by plotting the graph of both inequalities

Because both inequalities do not have any form of equation i.e. ≤ and ≥, then only the points in the shaded area represents the solution set of the inequality.

The points in the shaded area are (-6,-5) and (-4,-4)

Other points are either outside the shaded area or on the line of the inequalities

Hence, the solution set of the system of linear inequalities are (-6,-5) and (-4,-4)

consider the system of linear inequalities {y<1/2x-1, y>2x+3} Which points are in the solution set?a. (-4,-3)b. (1,3)c. (-5,-7)d. (3,0)e. (-6,-5)f. (-7,-2)g. (-4,-4)h. (-3,-3)

Respuesta :

How to determine the solution set?

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consider the system of linear inequalities {y<1/2x-1, y>2x+3} Which points are in the solution set?
a. (-4,-3)
b. (1,3)
c. (-5,-7)
d. (3,0)
e. (-6,-5)
f. (-7,-2)
g. (-4,-4)
h. (-3,-3)