Question : -
4/3 of a number is more than 3/4 of its number by 1 . find the number .
Given : -
- 4/3 of a no. is more than 3/4 of its no. by 1
To Find : -
- We have to find the number .
To Assume : -
So Solution goes from here :
According to question 4/3 of a number is equal to :
[tex] \longmapsto \: \frac{4}{3} \times x[/tex]
Which means ,
[tex]\longmapsto \: \frac{4x}{3} [/tex]
According to question 3/4 of a number is equal to :
[tex]\longmapsto \: \frac{3}{4} \times x[/tex]
Which means ,
[tex]\longmapsto \: \frac{3x}{4} [/tex]
Now , forming equation :
As the question says that 4/3 of a number is more than 3/4 of its number by 1 . So :
[tex]\longmapsto \: \frac{4x}{3} = \frac{3x}{4} + 1[/tex]
Now , transposing 3x/4 to left hand side :
[tex]\longmapsto \frac{4x}{3} - \frac{3x}{4} = 1[/tex]
Now , taking L.C.M :
[tex]\longmapsto \: \frac{4(4x) - 3(3x)}{12} = 1[/tex]
Now by calculating :
[tex]\longmapsto \: \frac{16x - 9x}{12} = 1[/tex]
Now Subtracting 16x with 9x and transposing 12 to right hand side :
[tex]\longmapsto \: 7x = 12[/tex]
So ,
[tex]\longmapsto \: \boxed{ \bold{ x = \frac{12}{7} }}[/tex]
- Therefore , the number is 12/7 .
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