zzgg7767 zzgg7767
  • 16-04-2022
  • Mathematics
contestada

express secA in terms of tanA​

Respuesta :

Hrishii
Hrishii Hrishii
  • 16-04-2022

Answer:

[tex] { \sec} A = \sqrt{1 + { \tan}^{2} A } [/tex]

Step-by-step explanation:

[tex] { \sec}^{2} A = 1 + { \tan}^{2} A \\ \\ \implies \: { \sec} A = \sqrt{1 + { \tan}^{2} A } [/tex]

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