Respuesta :
Given Equation :
[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + 9x - 22 = 0 \:}}} \\ \\[/tex]
To Find :
- The value of x .
Solution :
[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + 9x - 22 = 0 \:}}} \\ \\[/tex]
We are to find two numbers such that,
[tex]\\ {\longrightarrow \pmb{\sf {\qquad p + q = 9 \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad p \times q = 22 \:}}} \\ \\[/tex]
The two numbers are 2 and 11, so
[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + ( - 2x) + 11x - 22 = 0 \:}}} \\ \\[/tex]
Finding common factors :
[tex]{\longrightarrow \pmb{\sf {\qquad {x} (x - 2) + 11(x - 2) = 0 \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad (x - 2)(x + 11) = 0 \:}}} \\ \\[/tex]
Whether, the value of x is :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad (x - 2) = 0 \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad x = 2 \:}}} \\ \\[/tex]
Or, Whether the value of x is :
[tex] \\ {\longrightarrow \pmb{\sf {\qquad (x + 11) = 0 \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\sf {\qquad x = - \: 11 \:}}} \\ \\[/tex]
So,
- Therefore the value of x is (-11) or 2.
Answer:
A) –11
D) 2
Step-by-step explanation:
Got it right on edge!