Two person Pratham and Roshan are 64 km apart. If they walk in opposite direction then they will meet in 4 hours and in the same direction they will meet in 16 hours. Find their separate velocity. ​

Respuesta :

Using the relation between velocity, distance and time, it is found that:

  • Pratham has a velocity of 10 km/h.
  • Roshan has a velocity of 6 km/h.

What is the relation between velocity, distance and time?

Velocity is distance divided by time, that is:

[tex]v = \frac{d}{t}[/tex]

In opposite directions, the relative velocity is [tex]v = v_1 + v_2[/tex], and the 64 km are run in 4 hours, hence:

[tex]v_1 + v_2 = \frac{64}{4}[/tex]

[tex]v_1 + v_2 = 16[/tex]

[tex]v_1 = 16 - v_2[/tex]

In the same direction, the relative velocity is [tex]v = v_1 - v_2[/tex], and the 64 km are run in 16 hours, hence:

[tex]v_1 - v_2 = \frac{64}{16}[/tex]

[tex]v_1 - v_2 = 4[/tex]

Since [tex]v_1 = 16 - v_2[/tex]:

[tex]16 - v_2 - v_2 = 4[/tex]

2v2 = 12.

v2 = 6.

v1 = 16 - 6 = 10 km/h.

Hence:

  • Pratham has a velocity of 10 km/h.
  • Roshan has a velocity of 6 km/h.

More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569