contestada

You need to make a generator for your bicycle light that will provide an alternating emf whose peak value is 4.2 V. The generator coil has 55 turns and rotates in a 0.040-Tesla magnitude magnetic field.

If the coil rotates at 400 revolutions per second, what must the area of the coil be to develop this emf?

Respuesta :

onyebuchinnaji

The area of the coil must be 7.6 x 10⁻⁴ m².

Peak induced emf

The peak emf induced in a coil is determined by applying Faraday's law of electromagnetic induction as shown below;

emf(peak) = NBAω

Where;

  • ω is the angular frequency in rad/s
  • A is the area of the coil
  • N is number of turns
  • B is magnetic field strength

[tex]\omega = 400 \ \frac{rev}{ s} \times \frac{2\pi \ rad}{1 \ rev} \ = 2,513.6 \ rad/s[/tex]

[tex]A = \frac{emf (peak)}{NB\omega} \\\\A = \frac{4.2}{55 \times 0.04 \times 2,513.6} \\\\A = 7.6 \times 10^{-4} \ m^2[/tex]

Thus, the area of the coil must be 7.6 x 10⁻⁴ m².

Learn more about peak induced emf here: https://brainly.com/question/24487261

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