Respuesta :

Answer:

[tex]4x ^{2} - 2x - 42 \\ 2(2 {x}^{2} - x - 21) \\ 2(2 {x}^{2} + 6x - 7x - 21) \\ 2(2x(x + 3) - 7(x + 3) \\ 2(2x - 7)(x + 3)[/tex]

Answer:

2x - 7

Step-by-step explanation:

4x² - 2x - 42 ( factor out 2 from each term )

= 2(2x² - x - 21) ← factor the quadratic

consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 21 = - 42 and sum = - 1

the factors are+ 6 and - 7

use these factors to split the x- term

2x² + 6x - 7x - 21 ( factor the first/second and third/fourth terms )

= 2x(x + 3) - 7(x + 3) ← factor out (x + 3) from each term

= (x + 3)(2x - 7)

then

4x² - 2x - 42 = 2(x + 3)(2x - 7) ← in factored form

with 2x - 7 as a factor