Respuesta :

Given :

  • Base = 2 m and 6 m.

  • Area = 60 m².

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To find :

  • The height.

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Solution :

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We know,

[tex]{ \longrightarrow{\qquad \sf{ \pmb {\dfrac{1}{2 } \times (b_{1} + b_{2}) \times h = {Area_{(Trapezoid)} } }}}}[/tex]

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Now, Substituting the values :

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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{1}{2 } \times (2 + 6) \times h = {60 } }}}}[/tex]

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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{1}{2 } \times 8 \times h = {60 } }}}}[/tex]

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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{8}{2 } \times h = {60 } }}}}[/tex]

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[tex]{ \longrightarrow{\qquad \sf{ 4 \times h = {60 } }}}[/tex]

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[tex]{ \longrightarrow{\qquad \sf{ h = { \dfrac{60}{4} } }}}[/tex]

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[tex]{ \longrightarrow{\qquad \sf{ \pmb { h = {15} } }}}[/tex]

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Therefore,

  • The height of the trapezoid is 15 m .

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