What is the number of years it will take the investment to double? if Moe invests $ 7,500 in an account that pays 2.4% interest compounded monthly. Round your final answer to two decimal places.

Respuesta :

Answer:

  28.91 years

Step-by-step explanation:

The investment value is multiplied each year by the factor ...

  (1 +r/12)^12

  = (1 +0.024/12)^12 = 1.002^12 ≈ 1.024265768

When the investment is multiplied by this factor for x years, the multiplication factor becomes 1.024265768^x. We want to know the value of x that makes this equal to 2:

  2 = 1.024265768^x

  log(2) = x·log(1.024265768) . . . . . take logarithms

  x = log(2)/log(1.024265768) ≈ 28.91

It will take 28.91 years for the investment to double at 2.4% compounded monthly.