Answer:
B displays correct solutions for x² +9x +12 = 6
step-by-step explanation:
[tex]\rightarrow \sf x^2 + 9x + 12 = 6[/tex]
[tex]\rightarrow \sf x^2 + 9x +12 -6 = 0[/tex]
[tex]\rightarrow \sf x^2 + 9x + 6 =0[/tex]
use the formula: [tex]\sf \bold{x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a } \ \ when \ \ \ ax^2 + bx + c = 0}[/tex]
[tex]\rightarrow \sf x = \dfrac{ -9 \pm \sqrt{(-9)^2 - 4(1)(6)}}{2(1)}[/tex]
[tex]\rightarrow \sf x = \dfrac{ -9 \pm \sqrt{57}}{2}[/tex]
[tex]\rightarrow \sf x = \dfrac{ -9}{2} +\dfrac{\sqrt{57}}{2}[/tex] ; [tex]\sf x = \dfrac{ -9}{2} -\dfrac{\sqrt{57}}{2}[/tex]
