The equation of the sum of any two squares x and y is x^2 + y^2 = (x + y)^2 - 2xy
How to determine the last digit
The question is incomplete, as there are no parameters to determine the last digit of the first number.
So, I will give a general explanation
The sum of squares of two numbers x and y is:
[tex]x^2 + y^2 = (x + y)^2 - 2xy[/tex]
Assume the numbers are 5 and 6, then the equation becomes
[tex]5^2 + 6^2 = (5 + 6)^2 - 2*5*6[/tex]
Evaluate
[tex]5^2 + 6^2 = 61[/tex]
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