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what mass of magnesium bromide is produced when 35cm3 of 0.18 mol/dm3 of hydrogen bromide is treated with magnesium nitrate?

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Answer:

2

Explanation:

2 atoms of hydrogen each of mass 1 = 2 x 1 = 2 g mol–1

1 atom of sulphur of mass 32 = 1 x 32 = 32 g mol–1

4 atoms of oxygen of mass 16 = 4 x 16 = 64 g mol–1

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