The table of values represents a polynomial function f(x)
x f(x)
4 358
5 690
6 1178
7 1852
8 2742
9 3878
How much greater is the average rate of change over the interval [6,8] than the interval [5,7]?

The table of values represents a polynomial function fx x fx 4 358 5 690 6 1178 7 1852 8 2742 9 3878 How much greater is the average rate of change over the int class=

Respuesta :

Answer:    536

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Explanation:

The average rate of change is the same as the slope of the line through the endpoints mentioned.

The interval [6, 8] means that we're talking about [tex]6 \le x \le 8[/tex]

  • When x = 6, we have y = f(x) = 1178
  • When x = 8, we have y = f(x) = 2742

So we're tasked to find the slope of the line through (6,1178) and (8,2742)

We'll use the aptly named slope formula.

[tex](x_1,y_1) = (6,1178) \text{ and } (x_2,y_2) = (8,2742)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2742 - 1178}{8 - 6}\\\\m = \frac{1564}{2}\\\\m = 782\\\\[/tex]

The slope through those two endpoints is 782, which is the average rate of change on the interval [6, 8].

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For the interval [5,7] we have [tex]5 \le x \le 7[/tex]

According to the function table,

  • When x = 5, y = 690
  • When x = 7, y = 1852

Like before, use the slope formula to find the slope through (5,690) and (7,1182)

[tex](x_1,y_1) = (5,690) \text{ and } (x_2,y_2) = (7,1182)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{1182 - 690}{7 - 5}\\\\m = \frac{492}{2}\\\\m = 246\\\\[/tex]

This is the average rate of change on the interval [5,7].

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The last step is to subtract the slopes:

782 - 246 = 536 which is the final answer