contestada

The hypotenuse of a right triangle measures 15 cm and one of its legs
measures 9 cm. Find the measure of the other leg. If necessary, round to the
nearest tenth.

Respuesta :

CoastsideDad

Answer:

12

Step-by-step explanation:

Use Pythagorean Theorem

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

[tex]9^{2}[/tex] + [tex]b^{2}[/tex] = [tex]15^{2}[/tex]

81 + [tex]b^{2}[/tex] = 225

[tex]b^{2}[/tex] = 144   (subtract 81 both sides)

b = 12      (square root each side)

Given -

➣ The hypotenuse of a right triangle measures 15 cm.

➣ one of its legs (base) measures 9 cm.

To find -

➣ the measure of the other leg (perpendicular).

➣ to round the answer to nearest tenth.

Solution -

Here,

p = perpendicular of the triangle

b = base of the triangle

h = hypotenuse of the triangle

Using the Pythagoras Theorem,

(height)² = (perpendicular)² +(base)²

i.e h² = p² + b²

➩ (15)² = p² + (9)²

➩ p² = (15)² - (9)²

➩ p² = 225 - 81

➩ p² = 144

➩ p = √144

➩ p = 12 cm

Hence, the measure of the other leg is 12cm.

_____________________________

12

⇣

__

10

__

Round 12 to nearest tenth gives 10 as the answer.

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