contestada

A helicopter hovers 200. 0 meters over the ground and releases a relief packet. How much time does it take for the food packet to reach the ground?

Respuesta :

This solution assumes that there are no air resistance and no wind and thus no drag to the object itself

Based on the information given:

  • inital height = 200
  • final height = 0 or groundlevel
  • no intial velocity
  • acceleration: -g or 9.8m/s^2  (gravitional acceleration)

With that information at hand, we use the physics equation:

      [tex]x = x_{intial-height} +v_{intial-velocity}+\frac{1}{2}at^2[/tex]

  • a: acceleration
  • t: time taken for the fall
  • x: (with no subscript) is the final height

Now let's plug in all the known variables and solve.

     .[tex]0 = 200-\frac{1}{2}*9.8t^2\\ \frac{1}{2}*9.8t^2 = 200\\4.9t^2 = 200\\t = 6.389s[/tex]

Thus it takes the food packet approximately 6.389 seconds to hit the ground.

Hope that helps!