This solution assumes that there are no air resistance and no wind and thus no drag to the object itself
Based on the information given:
With that information at hand, we use the physics equation:
[tex]x = x_{intial-height} +v_{intial-velocity}+\frac{1}{2}at^2[/tex]
Now let's plug in all the known variables and solve.
.[tex]0 = 200-\frac{1}{2}*9.8t^2\\ \frac{1}{2}*9.8t^2 = 200\\4.9t^2 = 200\\t = 6.389s[/tex]
Thus it takes the food packet approximately 6.389 seconds to hit the ground.
Hope that helps!