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There is a bag filled with 2 blue, 4 red and 5 green marbles.
A marble is taken at random from the bag, the colour is noted and then it is not replaced.
Another marble is taken at random.
What is the probability of getting 2 the same colour?
IN FRACTION FORM PLEASS

Respuesta :

Answer:

[tex] \frac{17}{55} [/tex]

Step-by-step explanation:

After taking one of the 11 marbles, there are 10 marbles left.

Probability of blue followed by blue is

[tex] \frac{2}{11} \times \frac{1}{10} = \frac{2}{110} [/tex]

Probability of red followed by red is

[tex] \frac{4}{11} \times \frac{3}{10} = \frac{12}{110} [/tex]

Probability of green followed by green is

[tex] \frac{5}{11} \times \frac{4}{10} = \frac{20}{110} [/tex]

Adding these probabilities, we have

[tex] \frac{2 + 12 + 20}{110} = \frac{34}{110} = \frac{17}{55} [/tex]

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