Answer:
Step-by-step explanation:
5 + d < 5 - d
Add 'd' to both sides
5 + d + d > 5 - d + d
5 + 2d > 5
Subtract 5 from both sides
5-5 + 2d > 5 - 5
2d > 0
d > 0
The value of d is all positive integers
Answer:
[tex]\huge\boxed{\boxed{\sf{d > 0}}}[/tex]
Step-by-step explanation:
Hello.
First, move all the d's to the left. Be sure to use the opposite operation.
5+d>5-d (in this case, we subtract d, so the opposite operation is: add d)
5+d+d>5-d+d
The d's cancel out on the right:
5+d+d>5
Add the d's (they are like terms)
5+2d>5
Now, move 5 to the right, using the opposite operation:
5-5+2d>5-5
The 5's cancel out on both sides:
2d>0
Divide both sides by 2:
d>0, since 0 divided by 2 is 0 :)
And we're done!
I hope it helps & have an outstanding day!
~ST2710 :)
