Step-by-step explanation:
well, now, what did you understand from the solution of the previous problem ? that is why I tried to write down really every step and thought to get to the solution.
still unclear ?
again, we have 2 unknowns : length and width of the practice court.
L = length
W = width
we know that the width is 16 ft less than the length.
so,
W = L - 16
of course, we could also write L = W + 16. it says the same thing.
the perimeter of a rectangle is defined by the "walking" distance when walnut around the whole rectangle twice.
and that means we have walk the length twice and the width twice.
so the perimeter is
P = 2L + 2W = 160 (in our case)
so our 2 equations for the 2 variables are again
W = L - 16
2L + 2W = 160
the first equation is already an identity existing one variable by the other, and we can use it in the second equation :
2L + 2×(L - 16) = 160
2L + 2L - 32 = 160
4L = 192
L = 192/4 = 48 ft
and from
W = L - 16
we get
W = 48 - 16 = 32 ft
the length is 48 ft, the width is 32 ft.
what is still unclear about how to do this ? what blocked you from finding the solution yourself ?
