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A convenient parameter for specifying the sensitivity of a radio telescope is its sensitivity in units of K/Jy; that is, the number of Kelvins of antenna temperature TA produced by an unpolarized point source whose flux density is 1 Jy. (a) What is the effective collecting area Ae of a radio telescope whose sensitivity is 1 K/Jy

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The effective collecting area of this radio telescope with a sensitivity of 1 [tex]\frac{K}{Jy}[/tex] is 2761 square meters.

Given the following data:

  • Antenna temperature = 1 K.
  • Flux density = 1 Jy.

How to determine the sensitivity of a telescope.

In Science, the sensitivity of a radio telescope is its sensitivity and it is usually expressed by using a convenient parameter in units of [tex]\frac{K}{Jy}[/tex].

Mathematically, an antenna temperature produced by an unpolarized point source with respect to flux density is given by this formula:

[tex]T_A=\frac{SA_e}{2k}[/tex]

Making effective area the subject of formula, we have:

[tex]A_e=\frac{2kT_A}{S}[/tex]

Substituting the given parameters into the formula, we have;

[tex]A_e=\frac{2 \times 1.38065 \times 10^{-23} \times 1}{10^{-26}}\\\\A_e= 2761 \;m^2[/tex]

Read more on flux density here: https://brainly.com/question/24186165

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