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Answer:

74.5 g of NaOH is dissolved in water to 1.50L of Solution .

We have been asked to find the molarity of solution

Formula to calculate Molarity

[tex] \\ \bullet{\boxed{\blue{\bf {molarity= \frac{moles \: of \: solute }{volume \: of \: solution} }}}}[/tex]

First Let's find the Molar Mass of NaOH

[tex] \implies \sf \:molar \: mass \: of \: NaOH = 23 + 16 + 1 \\ \\ \implies\sf \:molar \: mass \: of \: NaOH =40g {mol}^{ - 1} [/tex]

[tex] \bf \: moles \: of \: solute \: = \dfrac{mass}{molar \: mass} [/tex]

Put the given value we get

[tex] \sf \implies \: moles \: of \: solute \: = \dfrac{74.5}{40} \\ \\ \sf \implies \: moles \: of \: solute \: = 1.8625 \: mole[/tex]

Now calculating the molarity of given solution

[tex] \\ \bullet{\boxed{\blue{\bf {molarity= \frac{moles \: of \: solute }{volume \: of \: solution} }}}}[/tex]

[tex] \sf \implies \: molarity \: = \dfrac{1.8625}{1.50} \\ \\ \sf \implies \: molarity \: =1.24 \: M[/tex]

So, the molarity of the solution is 1.24M

Option (A) is your correct answer.

Eduard22sly

The molarity of the solution prepared by dissolving 74.5 g of NaOH in water is 1.24 M (Option A)

What is molarity?

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of NaOH

  • Mass of NaOH = 74.5 g
  • Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
  • Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 74.5 / 40

Mole of NaOH = 1.8625 mole

How to determine the molarity

  • Mole of NaOH = 1.8625 mole
  • Volume = 1.5 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 1.8625 / 1.5

Molarity = 1.24 M

Learn more about molarity:

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