Considering the definition of empirical formula, the empirical formula is Ag₁N₁O₃= AgNO₃.
The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 63.5 grams of silver, 8.2 grams of nitrogen and 28.3 grams of oxygen.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
Silver: [tex]\frac{63.5 g}{107.87 \frac{g}{mole} } =[/tex]0.588 moles
Nitrogen: [tex]\frac{8.2 g}{14 \frac{g}{mole} } =[/tex] 0.586 moles
Oxygen: [tex]\frac{28.3 g}{16 \frac{g}{mole} } =[/tex]1.77 moles
The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
Silver: [tex]\frac{0.588 moles}{0.586 moles}[/tex]≅ 1
Nitrogen: [tex]\frac{0.586 moles}{0.586 moles}[/tex]= 1
Oxygen: [tex]\frac{1.77 moles}{0.586 moles}[/tex]≅ 3
Therefore the Ag: N: O mole ratio is 1: 1: 3
Finally, the empirical formula is Ag₁N₁O₃= AgNO₃.
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