If mom is heterozygous for brown eyes and dad has blue eyes, what is the probability of their child having brown eyes (B = brown eyes, b - blue eyes)
B isn't the answer!
A: 100%
B: 75%
C: 50%
D: 25%
I believe the answer is (C) 50%, seeing as how there's two parents, if there was one (somehow) the probability would be close to 100%. There's two though so 100/2=50 therefore I got 50%, sorry if my answer is incorrect.
