When the volume of a gas is changed from 3.75 L to 6.52 L, the temperature will change from 100. 0 K to 173.86 K.
Temperature of the given gas will be calculated by rearranging the ideal gas equation as:
V₁/T₁ = V₂/T₂, where
V₁ = initial volume of gas = 3.75L
T₁ = initial temperature of gas = 100K
V₂ = final volume of gas = 6.52L
T₂ = final temperature of gas = to find?
Putting all these values on the above equation and calculate for the value of T₂ as:
T₂ = (6.52 × 100) / 3.75 = 173.86 K
Hence, 173.86 K is the required temperature.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/25290815
